#A B C D question
12 messages · Page 1 of 1 (latest)
A=2
B=3
C=1
D=7
2317+231+23+2=
you can do it by rough inspection
start by assuming A is 2, A is either 2 or 1, so pick one to start with
then gradually work across, if you find 2 of them to be the same then move along 1 and try and get it to add up to roll over (like having 23 in the ones spot)
I didn't understand. I get that the values you gave does work but until C, Instantly my mind goes to say that it must be 2 if 2+3+C = 7. Then the D cannot be found. How did you guess that C must be 1
because 2 + 3 + 1 is not 7
it's what I said about getting it to roll over
because if you get the ones place to sum to 13 then you get +1 to the 10s
so above 2 would be too unnecessary
thats why we gone to 1 instead
and c cannot be 2 3