Help with inverse function.

[austere river]

Hello, I was trying to solve number 3 of 132* but my answer doesn't match with the book which is ||4/3 - x/24||

f(x)=8(4-3x)
=> y = 8(4-3x)
=> x = 32-24y
=> -24y = x-32
=> y = (x-32)/-24 (my answer)
Where did I do wrong?

[simple crown]

from the 3rd line is already wrong, should be:
y = 32 - 24x
24x = 32 - y
x = (32 - y)/24
f^-1(x) = (32 - x)/24

[deep anvil]

Both your answer and given solution are equivalent

[austere river]

swindle and mine's correct?

[austere river]

why is y minused if you're moving 32?

[deep anvil]

Yes

[austere river]

I'm also having problem with number 4 trying to get the answer ||(2-3)/2x||

f(x) = 3/4-2x
=> y = 3/4-2x
=> x = 3/4-2y
=> 3/4-2y = x
=> 3/-2y = x-4
=> 3/-2 = y(x-4) (and then stuck.. since i dont know how to get that -2 over numerator and divided by 2x)

[simple crown]

again, the 3rd line is wrong

how can you directly switch x and y?

[austere river]

I was told to swap y with x

[simple crown]

you do that after making x the subject