#Find the image of this function
18 messages · Page 1 of 1 (latest)
yes, but that doesn't have anything to do with the range
Let's see
That's true
So Im(f) = (-inf,inf)
Why (-inf,1)?
It has to be like (-inf,2] U (1,inf)
No need for that, a graph is much better
Tbh I've never made such a table
So you can show me solved examples
Yes
Ok so you just need to replace that one -inf to inf in your answer
Cuz it's coming down from inf to 1
It's not going up
Yes I'm talking about yours
First image