help me pls ill send feet pics

[carmine elbow]

the question is
2 numbers are chosen from 1-20, what is the probability of those 2 numbers being consecutive (with replacement)

i got 1/10 i think that is very wrong

but idk

[shut fable]

you have 20 numbers and you choose 2, so you have 20C2 different ways of getting numbers, how many possible ways are there to get 2 consecutive numbers?

20C2=190 btw

wait no it has replacement

then it's 20×20 which is 400

@carmine elbow

[rigid oasis]

20 × 20 = 400
20 - 1 = 19
hence 19/400

[carmine elbow]

ik its 20 x 20 for the sample space

but idk what u mean by 20 -1

btw u can have 2 numbers consecutive

eg the frist nuber is 17

u can get 16 or 18

[shut fable]

ah

[shut fable]

consecutive would exclude the possibility for 1 to come after something

[carmine elbow]

wdym

[shut fable]

just going up you have
1,2
2,3
3,4
4,5
...
19,20

which if you count is 19 different pairs

but that doubles if you can go both directions

leaving you with 19/200

[carmine elbow]

can u solve it without like counting pairs and stuff

[shut fable]

yes, with logic

[shut fable]

which is this

the pair is in-between each number, there are n-1 spaces between n numbers

[carmine elbow]

hm