Polynomial

[pure seal]

how to do

@analog matrix hi

please show me how u do it

@analog matrix are u typing still?

[analog matrix]

y = x
(x - 2k)² + (x - k)² = 1
x² - (4k)x + 4k² + x² - (2k)x + k² = 1
2x² - (6k)x + (5k² - 1) = 0
tangent -> D = 0
(-6k)² - 4(2)(5k² - 1) = 0
36k² - 8(5k² - 1) = 0
36k² - 40k² + 8 = 0
-4k² + 8 = 0
4k² = 8
k² = 2
k = ±sqrt(2)

[pure seal]

why do u equate

[analog matrix]

why is option (a) and (c) the same?

my answer isn't in the options

[pure seal]

error i think

did u make an error

so how come

so can u help me understand the discrmiannt

i thoguht discrmiantn was like intercepts

amount of solutions for intercepts

what does that got to do with the tangent

it means i dont know how discrmiannt works

or the application

[analog matrix]

in quadratic, if D = 0, then the parabola only intersect the x-axis at one point

same in this case

[pure seal]

isnt that the intercept

how do we know that the tangent

and circle

intercept and the intersect

[analog matrix]

cuz tangent only intersect at one point

[pure seal]

can u draw it

i dont get it

@analog matrix

[zealous verge]

Meaning a parabola which is tangent to the x-axis

That means its root are equal

You are confusing you're self with the circle tangent and this tangent