#factorisation
2 messages · Page 1 of 1 (latest)
-(x³ - 67x + 126)
= -(x³ - 4x - 63x + 126)
= -(x(x² - 4) - 63(x - 2))
= -(x(x + 2)(x - 2) - 63(x - 2))
= -(x - 2)(x(x + 2) - 63)
= -(x - 2)(x² + 2x - 63)
= -(x - 2)(x + 9)(x - 7)
2 messages · Page 1 of 1 (latest)
Anyone any idea how to factorise it
-(x³ - 67x + 126)
= -(x³ - 4x - 63x + 126)
= -(x(x² - 4) - 63(x - 2))
= -(x(x + 2)(x - 2) - 63(x - 2))
= -(x - 2)(x(x + 2) - 63)
= -(x - 2)(x² + 2x - 63)
= -(x - 2)(x + 9)(x - 7)