#area of polar curves
11 messages · Page 1 of 1 (latest)
,w r=2sin(theta)
Yeah but why
Is it because it’s larger than the circle with radius one or what?
this is wrong, if you calculate it like that you're calculating the area outside (above the shaded area), also the constant should be 1/2 not 2
so what you can do is subtract the area of r = 2 sin(ø) from 0 to pi/2 by the one you've written
btw r2 = 2 sin(ø) cuz it's larger and therefore become the outer curve
ohh yeah
Thank you so much