#area of polar curves

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shy pumice
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which of these two grphs should be r2 and why?

sharp mortar
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,w r=2sin(theta)

shy pumice
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Is it because it’s larger than the circle with radius one or what?

sharp mortar
# shy pumice which of these two grphs should be r2 and why?

this is wrong, if you calculate it like that you're calculating the area outside (above the shaded area), also the constant should be 1/2 not 2
so what you can do is subtract the area of r = 2 sin(ø) from 0 to pi/2 by the one you've written
btw r2 = 2 sin(ø) cuz it's larger and therefore become the outer curve