#can someone help please
5 messages · Page 1 of 1 (latest)
find 2 numbers p and q such that
p + q = 6
pq = -27
not hard
x^2 + 6x - 27 = 0
=> x^2 + 9x - 3x - 27 = 0
=> x(x+9)-3(x+9)
=> (x+9)(x-3)
@brisk plover am i right?
5 messages · Page 1 of 1 (latest)
hard question
find 2 numbers p and q such that
p + q = 6
pq = -27
not hard
x^2 + 6x - 27 = 0
=> x^2 + 9x - 3x - 27 = 0
=> x(x+9)-3(x+9)
=> (x+9)(x-3)
@brisk plover am i right?