#y=a(x-h)^2+k
28 messages · Page 1 of 1 (latest)
oh i see
ok so
since x = 0
the focus here would be a quarter or 1/4 because of the 1 being substituted in
in other words we would have (0, 1/4)
and because of this being found out we can start plotting
since we know that the vertex is (0,0) we leave that alone
then we work our way backward with our focus
Let me put out the points
that would be really helpful
yeah i’m sorry i usually get carried away with this stuff
thank you for listing those points down, if you could can you explain to me how you got the first X,Y
the (-2,4)?
yes!