#How to find the limit of this function?

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bleak heron
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Have I done it correctly?

true hinge
# bleak heron Have I done it correctly?

I assume you meant 1/(2x) in the power.
For x -> 0 we have tan(x) ~ x. So:
(1 + tan(√(3x))^2)^(1/(2x)) ~ (1 + √(3x)^2)^(1/(2x)) = (1 + 3x)^(1/(2x)), x -> 0
The rest is easy, just recall what the limit of (1 + x)^(1/x) for x -> 0 is.

bleak heron
true hinge
bleak heron
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Ahh did it come from the known identity that lim x->0 tanx/x=1 btw?