#How to find the limit of this function?
5 messages · Page 1 of 1 (latest)
I assume you meant 1/(2x) in the power.
For x -> 0 we have tan(x) ~ x. So:
(1 + tan(√(3x))^2)^(1/(2x)) ~ (1 + √(3x)^2)^(1/(2x)) = (1 + 3x)^(1/(2x)), x -> 0
The rest is easy, just recall what the limit of (1 + x)^(1/x) for x -> 0 is.
Oh btw how did you assume that tanx ~ x?
I didn't assume it, it's a known thing.
Since tan(x) = x + O(x^3) for x -> 0, that means tan(x) ~ x for x -> 0.
Ahh did it come from the known identity that lim x->0 tanx/x=1 btw?