#Linear independent vectors

27 messages · Page 1 of 1 (latest)

grim fern
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That is the definition of linear independence.

drowsy ivy
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Yeah but why is it

grim fern
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What do you mean "why"? It is the definition.
A collection of vectors are linearly dependent if there is a nontrivial linear combination of them that is equal to the zero vector.

drowsy ivy
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And why is this the definition

grim fern
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I don't understand the question.

sterile arch
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Probably asking why we defined it like that

grim fern
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Oh.

drowsy ivy
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I don't expect the man who came up with this definition he had nothing in mind and decided on this thing to be "linear independence"

grim fern
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Well, that's because we are usually interested whether n vectors make up a basis of ℝ^n (or the n-dimensional space they are defined in, anyway).
And that only happens when they are linearly independent.

sterile arch
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Right and the definition shows that vectors are linearly independent

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Because let's say a, b and c are not all zero right

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And the sum is still equal to 0

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Then that must mean that one vector is a scalar multiple of another

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And hence linearly dependent

grim fern
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But it might happen.

drowsy ivy
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ye

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I was about to say that

grim fern
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Oh, or did you mean the nontrivial linear combination of them is equal to zero?

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Then yes.

sterile arch
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Yes sorry my English isn't all that great at times haha

drowsy ivy
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trivial like all the coefficients are 1?

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Or what

grim fern
drowsy ivy
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Ok

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How do I close this post now?