#System for a,b,c positive
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I found the 4 (a,b,c) solutions 😄
how?
I used inequalities of average
Let x = a/b ; y = b/c and z = c/a
now we have x^2+y^2+z^2=3
So the quadratic average is equal to 1
and we can notice that xyz=1
so the geometric average is also 1
and with average inequalities we know that GM<AM<QM
so (x+y+z)/3 = 1
The only solutions for (a,b,c) are (1,1,1) (3,3,-3) (3,-3,3) (-3,3,3)
the other method is using number theory :
we want the sum of 3 fractions be equal to 3
so a^2=b^2=c^2
This is enough to conclude 😄