functions defined at x=pi | Mathematics | Page 1

unique dune Jan 22, 2023, 10:34 PM

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I am confused on how to approach this problem.

cedar heart Jan 22, 2023, 10:49 PM

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• sin(x) is defined for x∈ℝ
• csc(2x) is 1/sin(2x) and sin(2x)=0 when x=π, can't divide by 0 so undefined
• cos^-1(x) is only defined for -1≤x≤1 so undefined for x=π
• sec^-1(x) is define for x∈{ℝ: x≥1,x≤-1} so yes it's defined for π

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in summary you gotta look at what these functions actually are

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for inverse functions the domain of them is equal to the range of their base function

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so sin^-1 has a domain of -1≤x≤1 because sin has a range of -1≤y≤1

unique dune Jan 22, 2023, 10:58 PM

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Oh that does make sense. It was simpler than I was thinking. Just got overwhelmed with all the trig function

#functions defined at x=pi