#surface area of cylinders
1 messages · Page 1 of 1 (latest)
I'll do 2 anyway
so to start off you have:
2 flat rectangles
2 half circle arcs
inside and outside arc
the rectangles are (20-12)×50 so 400cm²
the half circle arcs are 2(½πr²-½π(r-4)²) so 100π-36π=64π
inside arc is ½2πr so πr×50 for inside and outside
inside: 50×π×6=300π
outside: 50×π×10=500π
together you have (500π+300π+64π+400)cm² or (864π+400)cm² which is roughly 3114cm²
your amazing