#Limits

39 messages · Page 1 of 1 (latest)

latent cosmos
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Instructor never covered this in class... need help

lapis magnet
latent cosmos
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yes

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like a backwards L

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kinda

lapis magnet
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Alright.
So, what happens when x is positive and large (so, for x -> +∞)?

latent cosmos
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ohhh so what happens to y?

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it goes to infinity right

lapis magnet
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Yes.

latent cosmos
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oh oh oh ok

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i get it now

lapis magnet
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And what about large negative numbers (x -> -∞)?

latent cosmos
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it goes to 0

lapis magnet
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Yes.

latent cosmos
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well the limit

lapis magnet
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So, the correct option is the selected one.

latent cosmos
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one more question

lapis magnet
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Yes?

latent cosmos
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instructor never taught us x -> to infinity

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just x to whole numbers

lapis magnet
# latent cosmos

So, here is how you deal with limits of rational functions when x -> +∞ or x -> -∞.
First of all, determine the power of the polynomial in the numerator and denominator.

latent cosmos
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2

lapis magnet
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Yes, both 2.
Then, you need to divide each term in the numerator and the denominator by x to the maximum power. In this case, by x^2. What will you get?

vivid swan
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then you use the identity that n/x x→∞ is 0

lapis magnet
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Yes.

vivid swan
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leaving 7/14 aka ½

lapis magnet
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Basically, all the terms except the leading ones will have the form const/x^n, so their limit will be 0.
Thus, only the leading terms determing the value of the limit.

latent cosmos
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i got (7 - 6/x - 17/x^2) / (14 + 2/x - 11/x^2)

vivid swan
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now you do direct sub

lapis magnet
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Yes, that's correct.
So, now observe that everything except 7 and 14 goes to 0 when x -> ∞.

vivid swan
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6/∞ is 0 and 17/∞² is 0

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so on

latent cosmos
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so the answer is 1/2?

lapis magnet
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Yes.

latent cosmos
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can you use this method everytime there is a polynomial?

vivid swan
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yes

latent cosmos
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ok bet

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thanks