#Ditzenel’s help with Precalculus.
23 messages · Page 1 of 1 (latest)
post a screenshot of a few questions and your queries then ill help out
Ok.
yes
The first two pictures are connected. I don’t really get them at all.
so for f-g you need to find the value of f at a point on x and the value of g at a point on x, then connect them with a smooth line.
Example:
x=-2, f-g=-0.5
x=-1, f-g=1
x=0, f-g=1.5
x=1, f-g=2-1=1
x=2, f-g=1.5-2=-0.5
for height and weight you just substitute in your function for h so you get 40(t/9+3)-120, then you expand your brackets to get 40t/9+120-120=40t/9, and this gives you the weight of the boy as a function of his age
for average slope you would do rise over run on the interval [5,7], you know your run is equal to 7-5 and your rise is f(7)-f(5) so -42--20 so -22 (double negative is positive), which leaves you with -22/2 or -11
for the next question its a similar scenario, you do 7-6=1 and 1/7-1/6 where you cross multiply and get 6/42-7/42 so -1/42 which you now divide by 1 and get -1/42
thats absolutely fine
Okay. Wrote it down. Thanks for the help, Alex.
Now for the next part in my homework. I’ll bring up pictures next time if I don’t get them.
no problem
And it became more complicated since I was never taught any of this.
if the insides of a bracket are multiplied then you can just multiply the power of the bracket onto the exponent of each of the inside parts, and when dividing values of the same base you subtract the exponents
I see.
i can't help you with all of those unfortunately, pick a few really important questions and i can do those
for the top it becomes (x-0.5)^2-0.25+7 which becomes (x-0.5)^2 + 6.75
middle becomes -2x(12x-10x^2-30+25x) which is -2x(-10x^2+37x-30) which becomes 20x^2 - 72x + 60
bottom becomes x+7=(x+3)(x-3) which is x+7=x^2-9 which then goes to 0=x^2-x-16 where you can factorise to get (x-0.5)^2 - 0.25 -16 so (x-0.5)^2 - 16.25 = 0 so +/-sqrt(16.25)+0.5=x
Okay.