#Limits
11 messages · Page 1 of 1 (latest)
Are you talking about the limit of (e^(nx) - 1)/x as x -> 0? Let's see.
Suppose f(x) = e^(nx). Then our limit becomes:
(f(x) - f(0))/x, x -> 0
By the definition of derivative, that tend to f'(0):
(f(x) - f(0))/x -> f'(0), x -> 0
So, let's find f'(0).
f'(x) = ne^(nx)
f'(0) = n
So, the limit is equal to n. In case of e^(3x), that would be 3.
no derivative use
Ah. Hm... What can you use, then?
Can you use the limit definition of e, then?
yes
Ah, fantastic.