#Trig problem, it shouldn't be tough, but it is
42 messages · Page 1 of 1 (latest)
Basically, I got this function
Problem: when alpha tends to 90, the height tends to 0, and it can not tend to 0, as it is constant
Goal: Learn how can I improve the function to keep h constant, as it is in "reality"
What exactly needs to be found?
let's say a balloon, it's mostly a numerical problem, no statement, no context
Or is it needed
I think, that the 111m per degree is the causer
No, I mean I don't exactly understand what's going on in the problem.
I have to guess h By any method, simpler better
i only have alpha
Well
I don't have to guess the height
I have to create a function
height depending on the angle
Anything remaining to explain?
Well, are there any ther restrictions? Because what I can see doesn't restrict the height of h at all.
I can see that the lines AA and BB are parallel, that's no problem. But that doesn't restrict the length of BB.
BB has the same length as AA
We can call C and D the bottom ones
Oh, I see! Then it's easy.
tan(β) = AA/x
AA = x tan(β)
h = x tan(β)
In terms of α:
h = x cot(α)
You said that when α -> 0, we have h -> 0. That is only valid when x is constant.
In fact, X is alpha*111m
Each degree is 111m in the surface
What is 111 m?
meters
Wait, wait. Degrees can't be meters. Degrees measure angles, length measures lines.
I know
But there's a relationship
For each degree, the surface is 111m
Like the Earth's latitude
x can't depend linearly on α.
Is there any way to make it depend on α?
Well, x = h tan(α).
And, if x is linearly dependant on α, what errors should I expect?
Oh okay
so Tan(1°) = (x/111) / h
