#similar triangles prove
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ABC and BDC have a common angle B and a common side BC.
So, prove that their respective sides near that angle are in the same ratio, so AB/BC = BC/BD.
okay I'll try ty
ABD or ADB
Which is vertex?
Ah, sorry. I meant ABC, let me correct it.
it's ok 🙂
common angle is B
Ah, right! Sorry. Guess my eyes and brain took a vacation for this problem...
It's ok, ty both