How to multiply this
#algebra common doubt
misty radish
No need.
north wind
What my doubt is should I multiply 4 inside 1st or
Exand the algebra identity
I know thers no need....
My teacher 100% wants me to form a qudratic eq to make it more fun....
misty radish
First, collect everything on the left side.
9x^2 - 4(70 - x)^2 = 0
Then, use the difference of squares formula a^2 - b^2 = (a - b)(a + b):
(3x - 2(70 - x))(3x + 2(70 - x)) = 0
Simplifying a bit, we get:
(5x - 140)(x + 140) = 0
The rest is easy.
north wind
misty radish
You forgot the other solution.
north wind
Idk how to do that's why I left...
misty radish
If (x/(70 - x))^2 = 4/9, then x/(70 - x) = ±2/3, not just 2/3.
north wind
First, collect everything on the left side.
9x^2 - 4(70 - x)^2 = 0
Then, use the...
Can u explain my doubt I find this real hard
In urs A is like 2 variables and B is 2 variables too...
Yes..
misty radish
In urs A is like 2 variables and B is 2 variables too...
What do you mean? There is only one variable - x.
north wind
I meant you take all to left side
And apply a2 - b2
That's hard for me
Should I multiply 4 1st Or exand and multiply 4?
misty radish
You have 4(70 - x)^2, not (4(70 - x))^2. So, first expand the square, then multiply by 4.