help pls

[sterile ether]

if d is the distance from centre then we can draw a right angled triangle

whose hypotenuse is the radius

and base 1/2 of length of chord

since perpendicular from centre of the circle bisects the chord

from that we get
L=2(r^2-d^2)^(1/2)

and I guess domain is 0 to r

where r is radius of the circle

r=10

$L=\sqrt{100-d^2}$

[tiny oxide]

Scilent144