#Best strategy in worst case scenario
7 messages · Page 1 of 1 (latest)
If you had one phone you would have to drop it at every floor up until it breaks
With two, you can drop from every kth floor
The define a function drops(k)=floor(141/k)+k-1
Where you drop phone 1 every k floors
Then when it breaks trace back k floors, and drop k+1, k+2, etc
But be careful about what the worst case means here