#I can't figure out how to solve this system of equations. what am I doing wrong?

26 messages · Page 1 of 1 (latest)

rose jasper
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The best I can do with GE is eliminate one line to zeroes, and then if I try to back substitute that into the original problem, I get the wrong answer!

willow hearth
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"4x1 = x2" does not mean "any vector whose first entry is 4 times the second"

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Think carefully

rose jasper
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haaa, interesting. I guess it means "x_2 is four times greater than x_1" which would be [1 4] 😅

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thank you!

rose jasper
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it seems to me there has to be a more "linear algebra"-ey way to find this solution eigenvector without backsubstitution followed by some ad hoc algebraic interpretation

willow harbor
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You have to define the parameters first.

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In the firs case, the parameter is x1, and x2 depends on x1

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let's write x1 = t, then x2 = 4t

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So, in the firs position goes t and in the second, goes 4t

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Thus, the vector space can be writen as (t, 4t) = t*(1, 4)

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is a space generated by the vector (1; 4)

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In the second case you have a 2-dimensions vector space

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I can chose x1 = t and x2 = u

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and x3 = -4t - u

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so, the vector space can be represented as (t; u; -4t - u) = t*(1; 0; -4) + u*(0; 1; -1)

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So, any vector in this vector space can be written as a linear combinations of the vectors (1; 0; -4) and (0 ;1; -1). These are the generators of the vector space

rose jasper
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ohhh my gosh that's... a really interesting way to establish that. let me think on this for a while

willow hearth
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t(1; 0; -4) + u(0; 1; -1)

willow harbor
gritty skiffBOT
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@willow harbor has given 1 rep to @willow hearth

willow harbor
rose jasper
# willow harbor This concept is key in linear algebra courses. I assume you will start to see it...

yeah, I've actually taken a few linear algebra courses now and for some reason non of them have introduced this framing. I've seen two different flavors of linear algebra course material: 1) do trivial examples which the numbers line up such that you can solve them in your head and 2) figure out the general rules such that a programmatic solution can be applied.

and in neither of those paradigms is this framing you're discussing here approached

willow harbor
rose jasper