#Critical numbers Problem
5 messages · Page 1 of 1 (latest)
The critical points of a function is when the derivative equals zero
The derivative is given, so need to find when (or how many times)
5e^(-.1| x|)•sinx - 1 = 0
I’d probably try finding the derivative of f’(x) to find maxs/mins then use IVT to find how many zeros you have
Since sin(-x) = -sin(x), you could probably find it two cases, when x >= 0 and x < 0 (for the absolute value)
@tepid ice Oh thank you very much!