#Involution ,DIT ,DDIT
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Which part don't you understand
can you give me an example of a point "A" after involution
i don't understand what involution be like
Let L be a line
Let O be a fixed point on L
f that send A to A' on the line L such that $OA \cdot OA' = 1$ is an involution
k12byda5h
wow ok
I know him personally. You can tell me what you don't understand
🙏 wow sir
thank you
in the pdf he defines, Let P, A, B, C, D be points on a plane with AB ∩ CD = E,AD ∩ BC = F. Let a conic C tangent to lines AB,CD,AD,BC. Let PX,PY are the tangent line from P to C. Then (PX,PY),(PA,PC),(PB,PD),(PE,PF) are reciprocal pairs of some involution on pencil of lines pass through P.
in the ddit i don't understand the italic part
why can we involution on lines
you understand the definition of involution of points on line right?
yes
In this case, it is involution of lines passing through a fixed point P. Let f is a funtion of those lines.
suppose that there is a fixed line L not passing through P
Let g be a function of points on line L such that
$$g(X) = L \cap f(\overline{PX}) \quad \forall X \in L$$
k12byda5h
Then f is an involution of lines if and only if g is an involution of points
To make it easy, we can just say that the projection of involution of lines on a line is an involution of points.
ok
okok
Let ABC and DEF be two triangles which share an incircle ω and cir- cumcircle γ. Let L be the tangency point of EF on ω and define K similarly on BC. Select N ≡ AL ∩ γ and M ≡ DK ∩ γ. Show that lines AM, EF, BC, ND are concurrent.
in this problem they said (DA,DM) is a pair
but idk why
pair of which involution
when you talk about involution, there must exist 3 pairs to uniquely determine an involution
but does the tangency at K do anything
He mentions DDIT on a triangle previously
it is
(DB,DC), (DE,DF),(DA,DK)
DDIT triangle is an special case of DDIT quadrilateral
ah yes
i understood now
By theorem 3, lines AM,EF,BC are concurrent. Similarly EF,BC,ND are concurrent
and we are done.
what is theorem 3 sir
Line $\overline{AA'}$ passes through a fixed point.
k12byda5h
when $A' = f(A)$ when $f$ is an involution on conic
k12byda5h