I'm pretty lost on how to solve this, any help is appreciated
#Help with quadratic
distant kiln
mild onyx
Ok so first lets lay out the variables and break it down
Golf Ball Trajectory function: -5t^2 + tx [a is given, c is y-intercept and has to be 0 in this case]
let x be the maximum height for Andrew
-5(4)^2 + b(4)= 0 [substitution of the roots]
-80 + 4b = 0
4b = 80
b = 20
[Now we figure out the maximum height for Andrew]
-5(2)^2 + 20(2) = 20 [The balls were at their peak at 2s --> -b/2a]
20 * 1.5 = 30 [max height for Ben]
-5(2)^2 + b(2) = 30 [substitution in the trajectory function for Ben]
-20 + 2b = 30
2b = 50
b = 25
Hence Ben's trajectory function is: -5t^2 + 25t
t = 0 or 5
Hence Ben's ball landed on the ground at 5s