# By the Pythagorean theorem, the hypotenuse is $\sqrt{2^2 +3^2}=\sqrt{13}$ \ \ Thus, $\sin \theta=\frac{2}{\sqrt{13}}$ and $\tan \theta=\frac{2}{3}$, meaning $\sin \theta+\tan \theta=\frac{2}{\sqrt{13}}+\frac{2}{3}$.