#Definite Integrals

40 messages · Page 1 of 1 (latest)

brazen bane
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Is it possible to find a new set of limits of integration of a definite integral after finding the area under a curve and the function?

Number 2 letter b

coral acorn
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Int(k,0) ydx = int(✓6,k) ydx
you take intervals [k,0] and [✓6,k]

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@brazen bane

brazen bane
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ok idk what to do to find k

coral acorn
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$\int_0^k\ f(x)\ dx\ = \int_k^{root 6} \ f(x)\ dx$

hearty dirgeBOT
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visionaryM

coral acorn
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@brazen bane solve for this

brazen bane
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yeah i know that but idk how

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@coral acorn

coral acorn
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Do You know substitution method???

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@brazen bane

brazen bane
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where does the 2x come from in the numerator

coral acorn
brazen bane
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why did u multiply both sides by 2

coral acorn
coral acorn
brazen bane
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ok idk that rule then

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is there another way to do this?

coral acorn
brazen bane
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bro what

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ok thanks theb

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then

coral acorn
# brazen bane bro what

No this is the only way if you are dealing with integration you should learn substitution property otherwise you're doomed

brazen bane
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my teacher hasnt taught us it yet tho :|

coral acorn
brazen bane
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ok can u help me with something else

coral acorn
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What is it???

brazen bane
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number 5

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i drew the graph and i know that it is a volume by washers

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but the graph when y is between 0 to 1 only has one function
our teacher told us that its the volume of the outside washer minus the inside washer

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so from 0 to 1 there is only one function so there is no outside or inside

coral acorn
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Show me the solution

brazen bane
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but from 1 to 4 there is an outside and inside function

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idk if u can see that well

brazen bane
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a solid is formed by revolving around x=-1

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but when y is between 0 and 1 there is only one function

coral acorn
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@brazen bane

brazen bane
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yeh and it revolves around x=-1 and forms a solid