#Definite Integrals
40 messages · Page 1 of 1 (latest)
ok idk what to do to find k
$\int_0^k\ f(x)\ dx\ = \int_k^{root 6} \ f(x)\ dx$
visionaryM
@brazen bane solve for this
where does the 2x come from in the numerator
x is already given
I multiply 2 both sides
why did u multiply both sides by 2
To use the substitution rule of integration
And multiplying both sides by same number doesn't change the equation
Nah
No this is the only way if you are dealing with integration you should learn substitution property otherwise you're doomed
my teacher hasnt taught us it yet tho :|
Then complain about him/her because for integration this property is very important
ok can u help me with something else
What is it???
number 5
i drew the graph and i know that it is a volume by washers
but the graph when y is between 0 to 1 only has one function
our teacher told us that its the volume of the outside washer minus the inside washer
so from 0 to 1 there is only one function so there is no outside or inside
Show me the solution
but from 1 to 4 there is an outside and inside function
idk if u can see that well
What about -1 to 0???
a solid is formed by revolving around x=-1
but when y is between 0 and 1 there is only one function
@brazen bane
yeh and it revolves around x=-1 and forms a solid