#Radius of Circle of which Angle of 3 Radiants Cutts off An Arc of 45 CM
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3 rad is the arc length
2πr=full circumference
(3/(2π))×2πr=45
(6πr)/2π=3r=45
r=15
It all makes sense to me, but if it's incorrect then I could actually spend some time on it
@eager mulch
yeah i was able to figure it out, ty tho for confirming im not insane
@eager mulch has given 1 rep to @fiery wedge
thank you
sec=1/cosθ
cotθ=(cosθ)/(sinθ)
arccot(2)=θ
1/cos(arccot(2))=√5/2
What would I do for this one? It is similar but uses tangent, wouldn't it be like sqrt(1 + x^2)/x
Or am I wrong
Ok cool so I did get it right
Then, would you happen to know how to solve this? I got -1
tan(15) would give you the slope of that line, the negative reciprocal of that would give you the slope of the original line
-1/tan(15) would be the slope
So -3.732
seems it
yes
And for this, z = 3e^(i(pi/2)), right
which year are you in university? these questions seem odd
I am learning pre calculus
so not in Uni?
No, but these questions are weird
We have multiple choice practice flyers we are given
So we can make sure we're up to snuff for a test
-3e^(iπ/2)
3e^(i3π/2)
Like for this question, the possible answers are:
z = e^i3pi/2
z = 3e^i3pi/2
z = 3e^ipi/2
z = epi/3
yeah my bad for the 3π/4
3e^ipi/2 would be 3i
have to go ¾ around or π/2 clockwise
so -π/2
2 solutions in 1 rotation, infinite solutions otherwise
Yeah ok that makes sense
I was just being dumb 💀
So, I have one more question that I don't understand entirely.
3e^i3π/2
3e^-iπ/2
-3e^iπ/2
-3e^-3iπ/2
2=4sinθ
0.5=sinθ
you can then do arcsin
θ=π/6,30°
asks for answer in radians
so just π/6
Is the amplitude of something always positive
Like y = -2 cos t + 3
Would amplitude be -2 or 2
Or either
always positive
Ok thought so