Exponential equation

[rotund bluff]

Is there any way to solve this, if so how would I do that? I couldn't find any information online for equations of this form.

[wary spoke]

ln9^x = ln4^3x-1 + ln1
xln9 - ln1 = 3x-1ln4
(ln9 - ln1)/ln4 = (3x-1)/x
???

Idk

[rotund bluff]

you can't do that first step

you have to take the log of the entire equation eg ln(4^(3x-1)+1)

which didn't really get me anywhere

[wary spoke]

Why can’t I do that

[nova echo]

because you would have to log the entire thing

there is no way to simplify it with basic operations

[wary spoke]

Oh ok my bad

[rotund bluff]

is there any way at all?

other than just using a calculator

[nova echo]

there is no way to do it

[rotund bluff]

damn

[split urchin]

,w solve 9^x = 4^(3x - 1) + 1