Finding X

[hardy vessel]

The question states 25 = 125 by the power of K.Find K

[foggy palm]

So 25^K = 125?

Or orther way

If so you can natural log both sides bring the K down and divide one by the other

Or
25^k = 125
(5^2)^k = 5^3
5^2k = 5^3
2k = 3
k= 3/2

[rustic burrow]

I think its the opposite

I mean he said 125 by the power of k

Mhm

$25 = 125^k \ \ 5^2 = (5^3)^k \ \ 5^2 = 5^{3k} \ \ 2 = 3k \ \ k = \frac{2}{3}$

[sturdy shuttle]

Mizere

[rustic burrow]

@hardy vessel ^

[hardy vessel]

Ohhhhh

Thank you