#Infinite Series
9 messages · Page 1 of 1 (latest)
lmao just ignore the troll
I suggest changing around the LHS until you get the familiar power series: $\sum^\infty_{n=1} \frac{(-1)^nz^n}{n}$
conquestace
Maybe try change of variable k=n+2 where (-1)^k-2 = (-1)^k
i got it btw thx guys