Can someone help pls

[wary hill]

Just need some explaining

[cunning spindle]

,rotate

[wary hill]

Its a series question

A-Level

[cunning spindle]

No test help

[wary hill]

wdym No test help

[cunning spindle]

It says "end of chapter 13 test"

[wary hill]

oh

fair enough then

[cunning spindle]

@normal gorge what do you think

[wary hill]

its for homework

[cunning spindle]

Is it a test if it says its a test on the paper

[normal gorge]

hmm

[cunning spindle]

It says 2017

Maybe he's from the past

[wary hill]

i have them at the end of each module at school

[normal gorge]

ok first of all isnt that physics

[wary hill]

nah math

u dont wanna see the next question lol

[normal gorge]

💀

oh its series

fuck a-level series i sucked at that

[wary hill]

tell me about it

[cunning spindle]

Initial height 1.5m. It bounces to a height calculated by the function

[wary hill]

this is the next lol

[cunning spindle]

The result is your new input for bounce 2

[wary hill]

oh

i can work from that

thank you

[cunning spindle]

41/50 * 1.5 gives you the next h

Makes sense yeah?

[wary hill]

yh

it was mainly the other parts

coz with part b, i used the a/r-1 forumla for infinite series

but i get a negative value

[cunning spindle]

The ball stops bouncing once the h is 0

[wary hill]

ok

but what would i do

[cunning spindle]

You drop it from a height, it travels down a distance d, then it bounces and travels 41/50*d, bounces and travels that distance again

[wary hill]

ok but how would i put that into a summation eq

[cunning spindle]

Would you just like the answer

[wary hill]

nah i wanna understand how to do it

[cunning spindle]

Whats the next one

[final idol]

Ephesians 2:8-9

Ephesians 2:8-9

Ephesians 2:8-9

Ephesians 2:8-9

[cunning spindle]

Set up the infinite sum

[wary hill]

sorry just wondering

where do u get the 2d from

[cunning spindle]

Ball hits floor, goes up and down the same height

So multiplied by 2 every time, except for the first height

@wary hill

[wary hill]

i have gotten to this

$d + 2d\sum_{n \ge 1}\left( \frac{41}{50}\right)^{n}$

[final idol]

Exie.