#Complex Numbers roots of cubics
29 messages · Page 1 of 1 (latest)
H α s ի
H α s ի
H α s ի
$\alpha \beta = \frac{c}{a}$
H α s ի
$\frac{1}{\alpha} + \frac{1}{\beta} = \frac{\alpha + \beta}{\alpha \beta}$
H α s ի
H α s ի
H α s ի
H α s ի
and so on
swindle
$\alpha\beta\gamma = -d/a$
swindle
tysm