#I dont know how to set up the integral for z pls help
7 messages · Page 1 of 1 (latest)
it's the integral of delta on the region defined by
z =< 1+x
z =< 1-x
0 =< z
0 =< y =< 3
think about it geometrically and you'll understand the first two inequalities
yea but how do i set up the integral with 2 upper bounds
they imply
z =< 1
so you just need to show that this system of inequalities is equivalent to
0 =< z =< 1
z-1 =< x =< 1-z
0 =< y =< 3
ok thank you!