#Why is part b true?

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woeful yoke
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Surely it becomes sin2x = 2 so sinx = 1 and so 90 is valid right?

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or is that waffle in top right meaning it cant be 1/2 pi radians

round ivy
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You can substitute 1 for tan(theta)+cot(theta) and then prove why 1=2cosec2theta has no solutions using trig rules