#Try to find this zero its hard for me
13 messages · Page 1 of 1 (latest)
Ok so for these kind of question, i dunno if this is a sure fire way of solving it, i like to make a substitution so that the last term disappears (coefficient of x is 0), which is -8 in this case
Notice how -8 = (‐2)^3
For u to understand what i mean, ill show u another example, since im not good at explaining
Now ignore the fact that you could just use a^3+b^3 identity on that
Now u can procced either by putting y = x+1 or just keeping as is
Notice how -3x^2 -3x = -3x( x+1)
Try doing the same for ur question
If someone has a better method then do that
Use the hit and trial and the factor theorem to factorise,
(x+1)(x-2)(x+4)
So the zeroes will be, -1,2,-4
use poly division like he said '
poly division and the factor theorem