Lawless's post(I m just creating it)

[lost rivet]

@potent current's post

@potent current use this

[potent current]

oh alright

wait so I post help here?

[lost rivet]

you post what you need help with here

[potent current]

oh alright thanks

2y^(2)-6y-9x=0 I actually need help with this

it's to find the vertex

using the -b/2a formula doesn't seem to work

I'm stuck with this :C

anyone?

[lost rivet]

is that the whole question ?

[potent current]

uhm yeah

idk how to find the vertex cuz -b/2a formula doesn't work with it

2y^(2)-6y-9x=0 this is the given

[potent current]

you know how tho?

[lost rivet]

I don't understand the question

vertex of what

triangle with something ?

[potent current]

vertex of x and y

for parabola

[lost rivet]

Ohhhh

so question 1

do you know differentiation ?

well actually we don't need that

@potent current what is your main issue with the question ?

[potent current]

uhm it's on how to get the x and y vertex tho

that's it pretty much

2y^(2)-6y-9x=0

[lost rivet]

no no not that

I mean whats different in this question for you

vertex is point of symmetery of the parabola

until now you have probably been dealing with such parabolas

@potent current right ?

[potent current]

uhm yeah that's a parabola

but idk how to get the vertex

of the given

that's my issue here

[lost rivet]

but in your current question

your parabola is different

[potent current]

yeah

[lost rivet]

its this type of parabola

[potent current]

oh

[lost rivet]

you can find vertex for this parabola right ?

[lost rivet]

y^2 = x
means sleeping parabola

[potent current]

that's the problem. I can't

[lost rivet]

x^2 = y means not sleepign parabola

can you find vertex of y=x^2 ?

using your normal way

[potent current]

the normal way was using the -b/2a formula

[lost rivet]

yup

[potent current]

but I keep getting the wrong answer

idk why

[lost rivet]

you do

and thats cuz that formula was not for sleeping parabolas

[potent current]

I think there's something that I should do

[potent current]

oh

[lost rivet]

imma tell you how to fix it in a min

[potent current]

so it's different formula/

[potent current]

alright2

[lost rivet]

nah, actually there is, but we won't use it

[lost rivet]

so first y = x^2

[potent current]

oks

[lost rivet]

use normal method on this

what do you get ?

[potent current]

wait lemme try

[lost rivet]

we will try this one in a min

[potent current]

I actually have no idea

this is my first time using different ways

[lost rivet]

use -b/2a

[lost rivet]

what did you previously use ?

[potent current]

-b/2a

that's the only formula I was taught

[lost rivet]

use that on y=x^2

what do you get ?

[potent current]

6/4

[lost rivet]

[potent current]

1.5

[lost rivet]

which question are you trying it on ?

[potent current]

is that it?

[potent current]

I'm using it for finding the x vertex

[lost rivet]

for $2y^2-6y-9x=0$ ?

[atomic loom]

Akki

[potent current]

x = 1.5 is wrong

I already consult my professor and he said it was wrong

[lost rivet]

well you are almost correct

[lost rivet]

1.5 is y vertex

[potent current]

huh

how

[lost rivet]

and what did you get for y vertex ?

[potent current]

with my previous calculations?

[lost rivet]

yup

[potent current]

It was way off than the real answer lmao

[lost rivet]

then lets do this

put 1.5 in place of y in equation

as 1.5 is y vertex

[potent current]

wait can you help me first find the x vertex?

like is there any specific formula

[lost rivet]

aight lets do this

[potent current]

or way

[lost rivet]

our parabola is sleeping

if we change x and y in equation

it will be a normal parabola right ?

[potent current]

hmm

idk what you mean but I'm getting the glimpse

[lost rivet]

the red one is parabola of your question

blue one is when I interchange x and y

[potent current]

I see

[lost rivet]

$2x^2 -6x-9y =0$

[atomic loom]

Akki

[potent current]

oh

[lost rivet]

now see their vertices

[potent current]

auh

[lost rivet]

whats the change in their vertices ?

[potent current]

x and y

[lost rivet]

x becomes y and y becomes x

thats why what you found was y vertex

[potent current]

with using the x vertex formula

[lost rivet]

and when you place it in equation $2y^2 -6y-9x=0$ you will get x vertex

[atomic loom]

Akki

[lost rivet]

yup :D

[potent current]

now I know the answer, but I still don't know how to solve it

[lost rivet]

now you know how to indentify when parabola is sleeping ?

[potent current]

yeah

[lost rivet]

without a graph

[lost rivet]

aight lets substitute

substitute 1.5

in place of y

in original equation

[potent current]

hmm

wait

[lost rivet]

2y^2 - 6y = 9x

[potent current]

what

you switch the 9x?

oh

[lost rivet]

its the same equation

[potent current]

which way is this finding the x vertex right?>

[lost rivet]

[potent current]

I think I'm starting to understand this

[lost rivet]

yayy

now one question

do you know what a vertex is ?

[potent current]

yeah

@lost rivet do you have the whole solving?

[lost rivet]

yup

$2y^2 - 6y - 9x =0$

[atomic loom]

Akki

[lost rivet]

substituting 1.5

$2(1.5)^2 - 6(1.5) - 9x =0$

[atomic loom]

Akki

[lost rivet]

$2(2.25) - 9 - 9x =0$

[atomic loom]

Akki

[lost rivet]

$4.5 - 9 = 9x$

[atomic loom]

Akki

[lost rivet]

$-4.5 = 9x$

[atomic loom]

Akki

[lost rivet]

x=-0.5

[potent current]

this is the x vertex?

[lost rivet]

it seems so

[potent current]

wait how did you come up with -0.5?

[lost rivet]

is it ?

[lost rivet]

-4.5 = 9x right ?

[potent current]

oh you divided it?

ok I see

-4.5/9

I see2

[lost rivet]

aha good