#Derivative
18 messages · Page 1 of 1 (latest)
What have you tried?
I tried substituting
2(3)-3-2/3+1
I don't seem to find the answer
Aside from the bottom being 4
...why are you plugging in values before differentiating?
That would just give you a constant, and the derivative of a constant is 0.
You just... use your derivative rules?
So do i use quotient rule?
Do you have a quotient?
It’s $2g’(x)-\frac{g(x)f’(x)-f(x)g’(x)}{g(x)^2}$
Daniel_The_Maniel
I think