2x^2 + 2y^2 +x -2y + 1 = 0 convert to standard form of a circle (x-h)^2 + (y-k)^2 = r^2
#Convert to Standard form of a Circle
honest dirge
sterile silo
completing the square
honest dirge
i get (x+1/4)^2 + (y-1/2)^2 = 7/8 im not sure tho 😭
sterile silo
just divide by two
honest dirge
on 0 as well?
sterile silo
i get (x+1/4)^2 + (y-1/2)^2 = 7/8 im not sure tho 😭
,w expand 2((x+1/4)^2 + (y-1/2)^2)
sinful nimbusBOT
honest dirge
wait im correct?
sterile silo
no
sterile silo
your radius value is wrong
sterile silo
no
honest dirge
hehhh
sterile silo
atleast thats not what im getting
sterile silo
$2 \left(x+\frac{1}{4} \right)^2 + 2 \left(y-\frac{1}{2} \right)^2 + \frac{3}{8} = 0$
sinful nimbusBOT
omegusnyan
honest dirge
**omegusnyan**
why is there a 2?
sterile silo
hm
sterile silo
$2x^2 + 2y^2 +x - 2y+\frac{5}{8} = 2 \left(\left(x+\frac{1}{4} \right)^2 + \left(y-\frac{1}{2} \right)^2 \right)$
sinful nimbusBOT
omegusnyan
sterile silo
do you agree
honest dirge
**omegusnyan**
i dont understand 😭
sinful nimbusBOT
omegusnyan
sterile silo
$x^2 + y^2 + \frac{1}{2} x - y + \frac{1}{2} = 0$
sinful nimbusBOT
omegusnyan
honest dirge
<@738367031925276713>
yes
sterile silo
yes
$x^2 + 2 \cdot \frac{1}{4} \cdot x + y^2 - 2 \cdot \frac{1}{2} \cdot y + \frac{1}{2} = 0$
sinful nimbusBOT
omegusnyan
sterile silo
yes?
honest dirge
**omegusnyan**
wHAt
honest dirge
**omegusnyan**
thats diff from mine
sterile silo
that dot represents multiplication
sterile silo
(x^2+1/2x+1/8)+(y^2-y+1/4)=-1/2+1/8+1/4
are you really telling me (1/4)^2 = 1/8
sterile silo
im going to steal your kneecaps
honest dirge
ahhaha
honest dirge
r^2 = -3/16
yayyyy i get -3/16 now
sterile silo
yayyyy i get -3/16 now
nice
sterile silo
so my final answer is (x+1/4)^2+(y-1/2)^2=-3/16... is it correct?
yep