snow river
const Foo = struct {
bar: u8,
baz: u8 = 42,
};
For the struct above, if I had to initialize all fields to undefined, I would do something like:
const foo: Foo = undefined;
How can I initialize all fields without a default value to undefined besides doing:
const foo = Foo{ .bar = undefined };
For structs with a large number of fields this can get pretty verbose.
bitter lintel
I dont exactly know but a suggestion would be to set the default value of bar to undefined, and then Foo{} would give you what you want
I dont think what you want exactly exists but you could do it with some comptime magic, but thats probably not worth the trouble
bitter lintel
pub fn initUndefined(comptime T: type) T {
const struct_info = @typeInfo(T).Struct;
var ret: T = undefined;
inline for (struct_info.fields) |field| {
@field(ret, field.name) = if (field.default_value) |default| @as(*const field.type, @ptrCast(default)).* else undefined;
}
return ret;
}
did it out of curiosity ^^