Zig build profile-specific output path | Zig Programming Language | Page 1

sterile spire Oct 30, 2022, 3:48 PM

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Hello! While using Zig I’ve found it slightly annoying that regardless of what profile I use Zig will overwrite any previous builds without indication of which profile the executable was compiled with.

How does one customize the profile-specific build path of an executable? I’d like to create a result similar to:

zig-out/
- ReleaseSafe/ 
- ReleaseSmall
- Debug

viral musk Oct 30, 2022, 4:42 PM

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Not sure what the right way is, if any, but this works:

const dir = std.fs.path.join(b.allocator,  &.{ b.exe_dir, @tagName(myexe.build_mode) }) catch unreachable;
myexe.setOutputDir(dir);

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which puts it in zig-out/bin/ReleaseFast etc

You can replace b.exe_dir with zig-out if you want your specific structure

sterile spire Oct 30, 2022, 7:15 PM

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@viral musk thank you!

dusty topaz Oct 30, 2022, 7:47 PM

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You can do also zig build -p NAME which will use ./NAME as the output directory, from the CLI.

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(p for 'prefix')

#Zig build profile-specific output path