warm sequoia
Guys
Let's assume that you have this line of code:
const foo:bar | void = foobar;
Type script won't make you use the properties of bar on foo because it doesn't exist on void, as it claims.
How can I fix this?
Assuming that bar is an object that has properties and foobar is an instance of bar
azure bluff
what if you use undefined instead of void?
warm sequoia
what if you use `undefined` instead of `void`?
nothing really changed, it sends the same error for some reason 🤔
azure bluff
I didn’t get the issue here. If you have a type guard or just a if(foo) then foo will be inferred as only bar
tepid plaza