Math is hard help

[proud perch]

well i think its like uhhh we split 22 shots in two so that means 11 shots each and then we substract 8 from marko and add it to ante so ante will have 11+8=19 and marko 11-8=3 and if we do 19+3=22

np!!!

[broken briar]

in terms of systems of equations, you set the number of hoops marko shot as m and ante as a.

ante shot 8 more than marko so
a=8+m

together they shot 22
a+m=22

so you just substitute a with the first equation
(m+8)+m=22

if you solve for m, m=7, so then you solve for a which means a=15

[signal monolith]

So what u 1st do is 22-8 en then do the answer of that divided by 2 so ex 22-8=14 then do 14:2

[karmic bluff]

you can do this in two ways that are similar.but this is the easier way . so you have two things we dont know : the amount ante shot and the amount marko shot . and we have two equations,so solving this is possible. first things we do is substitute ante and marko and write the first equation :ante = marko +8 . we know this is true because ante shot 8 more times than marko

then we write the other equation we have

ante + marko =22

now we know that the ante and marko in both of these

are equal

so we can exchange between them

one way pf doing this is substituting marko as ante + 8

again we know we can do this because ante = marko + 8

then now

the only thing we dont know is ante

so we just isolate ante

and we get the answer

dog shit explanation but here you go

hope it helped