#well it can t convert a float to a
arctic copper
by not trying to pass a float to a vector3 variable
hard elm
its from lerp itself cannot change that
north root
You computed smoothPosition for nothing here, did you mean to use that, instead of smoothSpeed on that last line?
transform.position = smoothPosition;
That would make more sense in this context
hard elm
you do understand why the error was showing up previously though?
do you mind explaining me?
arctic copper
do you mind explaining me?
c# is a strongly typed language, you can search more regarding that term to understand better. But as a summary, you can't assign to variables, values that are not of the same type of the variable. In this case, a vector3 variable will only accept vector3 values. There's a thing called casting though, that "bypasses" this, which you can also read more about it to understand properly.
hard elm
tysm so since i did this i casted the vectror 3?
arctic copper
no, because you're directly assigning a value of the same type, cast would be something like passing a vector3 to a vector2, not the same types, but similar enough that it can be used almost interchangeably in some cases.
