#I need help with camera's trigonometry.

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patent quarry
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as you can see in the image, the red ball represent where the mouse is in the scene as captured b the first part, the second one is where the ray is sended, only the ray is right.

image.png
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if I written anything wrong in the equation.

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also, the function that I'm using to calculate the triangle is this one
float DistanciaDaBaseDaCameraParaLocalSelecionado(float height, float angle)
//b(cateto) = tan(angle) * height(Outro cateto que temos)
=> Mathf.Tan(angle) * height;
}

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I need help with camera's trigonometry.