rarities | Official Unity Discord | Page 1

lone dawn Jun 22, 2023, 5:58 AM

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struct Rarity{
  string name;
  int likelihood; // Defined as inverse of probability.  So 1/10 would be 10.  Or 1/100 would be 100.
}

//This list needs to be defined with rarest item at top and least rare at bottom.
List<Rarity> rarities = new List<Rarity>{
  new Rarity("legendary",100000000),
  new Rarity("epic",1000000),
  new Rarity("rare", 1000),
  new Rarity("uncommon", 10),
  new Rarity("common", 0) // Last item is just catch all has to always be 0
};


int numberOfItemsToAssignRarities = 10000; // The number of items you want to generate

foreach(Rarity rarity in rarities){
  if (rarity.likelihood == 0){
    // The catch all rarity.  Anything that didn't get assigned a rarity
    Debug.Log($"There were {numberOfItemsToAssignRarities} of rarity {rarity.name}");
    break;
  }
  int randomNumber = Random.Range(0,rarity.likelihood+numberOfItemsToAssignRarities+1);
  int numberOfItemsOfThisRarity = randomNumber - rarity.likelihood;
  if(numberOfItemsOfThisRarity > 0){
    Debug.Log($"There were {numberOfItemsOfThisRarity} of rarity {rarity.name}");
    numberOfItemsToAssignRarities -= numberOfItemsOfThisRarity;
  }
}

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idk how well this would actually work. Just came up with it and typed it up in discord. No idea if it has compile errors or not

sturdy peak Jun 22, 2023, 6:04 AM

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tbh at a certain point. (definitely before 1e100) it’s all going to converge onto the same values

lone dawn Jun 22, 2023, 6:04 AM

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Yea... thought about that as well.

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Tricky little problem to solve.

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Could take the probability.
And do something like:

decimal probability = 0.001;
int items = 100;

float randomNumber = Random.Range(0.0, 1.0*items);
int itemsInRange = (randomNumber-(items*(1-probability)))/probability;
if(itemsInRange < 0){
  itemsInRange = 0;
}

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Though you're going to overflow your variables pretty quickly doing something like that

sturdy peak Jun 22, 2023, 6:08 AM

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I had a slight idea that would pretty much make the random generation O(1), by just partitioning a double (with value of 1) in a bunch of spots and multiplying each partition by 1e100. But then the issue is how to partition it.

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and i guess it would be pretty unnatural

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since a lot of the values would end with a 0000 or something

sharp oar Jun 22, 2023, 6:12 AM

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ending with a 0000 is not a problem

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since its not going to show all the digits

sharp oar Jun 22, 2023, 6:29 AM

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i noticed this is the main code

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'''
int randomNumber = Random.Range(0,rarity.likelihood+numberOfItemsToAssignRarities+1);
int numberOfItemsOfThisRarity = randomNumber - rarity.likelihood;
'''

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but i dont understand it

lone dawn Jun 22, 2023, 6:30 AM

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After thinking through it more don't think that first code block will work

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The second code block has a higher likelihood of working. But when your numbers get really big you'll overflow the vars and run into issues.

sharp oar Jun 22, 2023, 6:31 AM

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so this?
float randomNumber = Random.Range(0.0, 1.0items);
int itemsInRange = (randomNumber-(items(1-probability)))/probability;

lone dawn Jun 22, 2023, 6:31 AM

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yea

sharp oar Jun 22, 2023, 6:31 AM

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k

lone dawn Jun 22, 2023, 6:31 AM

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That code would generate the number of items of a specific rarity. Given the number of items and the probability of that rarity

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again untested. Just typed it up not sure if it's right

sharp oar Jun 22, 2023, 6:33 AM

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ok

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can the randomNumber be int?

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like without decimals

lone dawn Jun 22, 2023, 6:43 AM

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It has to be some kind of decimal variable.

sharp oar Jun 22, 2023, 7:04 AM

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now i have this

        float randomNumber = Random.Range(0.0, jps);
        BigInteger itemsInRange = (((int)(randomNumber*10000000000L)-((jps*(int)((1-probability)*10000000000L))/10000000000L)/10000000000L)/(int)(probability*10000000000L))/10000000000L;

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now the problem is i want it to be with bigint

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how can i do that?

#rarities