need help with loops task

[tawny sparrow]

can anyone help me to solve that

[floral badger]

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@tawny sparrow

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[untold otter]

what have you tried?

are you stuck on anything in particular?

[tawny sparrow]

    cin >> n;
    bool divisible = true;
    int i;

    for (i = 1; i < n; i++)
    {
        int origin = i;
        int q = origin % 10;
        if (q > 0){
            if (n % q == 0){
                divisible = true;
            }
            origin = origin / 10;
        } else {
            divisible = false;
        }
    }
    
    if (divisible == true){
        cout << i << endl;
    }```

[floral badger]

@tawny sparrow

It looks like you may have code formatting errors in your message

Note: Make sure to use back-ticks (`) and not quotes (')
Note: Make sure to specify a highlighting language, e.g. `cpp`, after the back-ticks

Markup

```cpp
int main() {}
```

Result

int main() {}

[tawny sparrow]

i have tried something like that

[untold otter]

you need to print each number that is divisible by its digits right

but you have 1 print statement outside your loop

so how are you going to print all those values if you only print once?

[tawny sparrow]

it's a big mistake

[untold otter]

also

for (i = 1; i < n; i++)
{
    int origin = i;
    int q = origin % 10;
    if (q > 0){
        if (n % q == 0){
            divisible = true;
        }
        origin = origin / 10;
        // ^ what do you think happens after this line is executed
    } else {
        divisible = false;
    }
}

[tawny sparrow]

if it is 123 as an example q will be 3 after that 2 and 1

[untold otter]

ah but will it?

[tawny sparrow]

i think no because of that divisible = true;

[untold otter]

        origin = origin / 10;
        // 1.
    } else {
        divisible = false;
    }
    // 2. out of the if
}

/// ---
// 3. back to the start of the loop
for (i = 1; i < n; i++)
{
    // 4. back to here
    int origin = i;// 5. make origin for the next i value

basicall your problem is that you have 1 loop

after you do origin = origin / 10 you're just going straight to the next loop iteration

the next value of i

[tawny sparrow]

i undestand it now

let me try again

[untold otter]

hint: you need to have whats called a nested loop

a loop inside another loop

[tawny sparrow]

i got it

    cin >> n;

    for (int i = 1; i <= n; i++) {
        int origin = i;
        bool divisible = true;

        while (origin > 0) {
            int q = origin % 10;
            if (q == 0 || i % q != 0) {
                divisible = false;
                break;
            }
            origin = origin / 10;
        }

        if (divisible) {
            cout << i << " ";
        }
    }

    cout << endl;

    return 0;```

[floral badger]

@tawny sparrow

It looks like you may have code formatting errors in your message

Note: Make sure to use back-ticks (`) and not quotes (')
Note: Make sure to specify a highlighting language, e.g. `cpp`, after the back-ticks

Markup

```cpp
int main() {}
```

Result

int main() {}

[tawny sparrow]

finally it works

the problem was about using second loop

i didn't get that i have to use nested loops

thanks for your help and time appreciate that @untold otter

[floral badger]

@tawny sparrow Has your question been resolved? If so, type !solved :)

[tawny sparrow]

!solved