String reverse assignment

[jade lantern]

#include <stdio.h>
#include <string.h>

int main() {
    char odd_string[10] = { '0', '1', '2', '3', '4', '5', '6', '7', '8'};
    char even_string[10] = { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9'};
    char empty_string[10];
    char single_char[10] = {'0'};

    for (int i = 0; i < strlen(odd_string); i++) {
    if odd_string[i] != Nan

        odd_string[i] = odd_string[strlen(odd_string) - i]
    }
}```

[halcyon locust]

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[jade lantern]

im not done building it but i wanted to know, how do we tell whether a place in a char array is not initialized

like if i actually put a value in it

nvm dont answer this i shall come back with more thought put into it

[jade lantern]

#include <stdio.h>
#include <string.h>

int main() {
    char odd_string[10] = { '0', '1', '2', '3', '4', '5', '6', '7', '8', '\0'};
    //char even_string[10] = { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9'};
    //empty_string[10];
    //char single_char[10] = {'0'};

    int i;
    for (i = 0; i < strlen(odd_string); i++) {
        if (odd_string[i] > 0) { // 0 = null so im assuming it should work
            char replacer = odd_string[i];
            char replaced = odd_string[strlen(odd_string) - i];

            odd_string[i] = replaced;
            odd_string[strlen(odd_string) - i] = replacer;

            printf("%s\n", odd_string);


        }
    }
}```

i ended cheating 😦 a lil but here is the solution i got

!solved