Why are character arrays ended with a '/0' while other ones do not have terminating characters?

[pearl wyvern]

I mean is it just a convenience thing, so we don't have to get the length of our strong when we want to use it?

[torpid needle]

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[errant topaz]

The \0 character does not mark the "end of the array". The \0 character marks the end of the string stored in a char array, if (and only if) that char array is intended to store a string.

[pearl wyvern]

That broadens my view of things thanks

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[torpid needle]

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[errant topaz]

From stack overflow there is a part that says there are multiple ways to declare character array.

Ex:

char str1[]    = "my string";
char str2[64]  = "my string";
char str3[]    = {'m', 'y', ' ', 's', 't', 'r', 'i', 'n', 'g', '\0'};
char str4[64]  = {'m', 'y', ' ', 's', 't', 'r', 'i', 'n', 'g' };

[quartz thistle]

Not all character arrays have \0 at the end. If you do char arr[] = {'a', 'b', 'c'};, it won't have one

But "abc" would. So there's no inconsistency between char and other types here